More digital silliness
Jack Brennen
jb at brennen.net
Wed Jan 9 23:13:43 CET 2008
Jack Brennen wrote:
>
> Since it appears that base 10 may not have any solutions, or
> at least none which are easy to find, perhaps there are
> some elegant solutions in other bases?
>
A really pretty one in base 14
(all representations in base 14 of course):
408^2 = 124848
59D^2 = 248481
804^2 = 484812
This is a cute pair (but still only a pair):
1222222222^2 = 1493827159950617284,
2222222221^2 = 4938271599506172841,
rotating the result by one place.
And here's a solution in base 23:
59L^2 = 16B964,
BL3^2 = 6416B9,
G4B^2 = B96416.
Bob
On Jan 9, 2008, at 2:33 PM, David W. Wilson wrote:
> Let an n-digit number be valid if it does not start or end with 0.
>
> Let a rotation of n be gotten by rotating its digits. Thus the
> rotations of 256 are 256, 562 and 625.
>
> We note that 256 has two valid square rotations, 256 and 625.
>
> Is there a number with more than two valid square rotations?
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