A025151 and A026826

Richard Mathar mathar at strw.leidenuniv.nl
Thu Jul 31 15:43:26 CEST 2008

I disagree.  Vacuously, all parts of the empty partition are >= 3, so 
there is one
partition of 0 into distinct parts >= 3.

Franklin T. Adams-Watters

-----Original Message-----
From: Richard Mathar <mathar at strw.leidenuniv.nl>

The (mild) problem that I see is that A025147 and A025148 have an 
offset of 0
which would mean "there is 1 partition of 0 into distinct parts >= 3," 
and this
is wrong.  As long as one extends the definition for A025147..A025155 
to the g.f. including the term 1*x^0, this is kind-of alright.
One ought perhaps split A025147 and A025148 into two different 
sequences each in
the manner it has been done for the higher k-numbers.

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