Has this problem been raised ?

[Alexander Povolotsky]

Hi,

floor((i/m)^n) + floor((k/m)^n) = floor((l/m)^n)

n > 2, m > 1, i > 0,  k > 0, l > 0, i != k

Has this problem been raised and resolved (one way or another) ?

Thanks,
Best Regards,
Alexander R. Povolotsky