RE : a(n) is the sum of the first a(n) digits
Eric Angelini
Eric.Angelini at kntv.be
Sat Mar 22 13:40:46 CET 2008
Same constraint, same building rule, but dropping the monotonicality is a nightmare to calculate by hand; help, please! ;-)
I get this:
1,10,2,4,100,101,11,12,13,14,30,1000,10000,40,41,100000,102,43,60,200,1000000,1001,61,80,1002,10000000000,90,10000000,103,104,10001,111,105,10003,91,...
Best,
E.
________________________________
De: Eric Angelini
Date: sam. 22/03/2008 11:02
À: seqfan at ext.jussieu.fr
Objet : a(n) is the sum of the first a(n) digits
Hello SeqFans,
I like this seq :
S=1,10,11,12,20,111,112,120,1000,1001,1002,1003,1004,1005,1006,1007,1008,1009,1010,1011,1012,1013,1014,1015,1016,10000,10000000000,10000000800,10000000801,10000000802,10000000803,...
... where a(n) is the sum of the first a(n) digits. (Example: "12" says that the first 12 digits sum up to 12, which is true: 1+1+0+1+1+1+2+2+0+1+1+1=12)
Seq is monotonically increasing and every new term must be as small as possible.
Could someone check this (and compute a few more terms)?
Best,
É.
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