[seqfan] Re: Prime Diophantine p = 2*q^2 + r.
Richard Guy
rkg at cpsc.ucalgary.ca
Mon Nov 24 19:35:37 CET 2008
Right, R.
On Sun, 23 Nov 2008, zak seidov wrote:
> --- On Sun, 11/23/08, Richard Guy <rkg at cpsc.ucalgary.ca> wrote:
>> 2*(6n +/- 1)^2 + (6m+1) = 3*(24n^2 +/- 8n + 2m +1)
>
> Me: in many cases q is 2 or 3 when your formula doesn't hold, right?
> zak
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