[seqfan] Re: Most efficient way to construct a list of pandigital palindromic numbers?
Alonso Del Arte
alonso.delarte at gmail.com
Tue Dec 8 06:10:02 CET 2009
Right, I'm saying "Duh!" to myself now.
Furthermore, 20-digit pandigital palindromes have a digit sum of 90 and a
digital root of 9. Hence, they're divisible by 99.
Al
On Mon, Dec 7, 2009 at 11:50 PM, Hans Havermann <pxp at rogers.com> wrote:
> > As for the 20-digit members of the sequence, I am certain the
> > explanation is
> > very simple...
>
> The answer is in the comment for A002385.
>
>
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