[seqfan] More conjectures on sequence products

[Richard Mathar]

Are these multiplication formulae known and/or profable:

A000302(n) = A046055(n)*A011782(n). (probably easy)

A002001(n) = A011782(n)*A003945(n). (probably easy)

id:A002450|id:A014551|id:A001045
A002450(n+1)= A014551(n+1)*A001045(n+1).

id:A003683|id:A001045|id:A000079
A003683(n+1)= A001045(n+1)*A000079(n).

id:A003947|id:A146523|id:A011782
A003947(n) = A146523(n)*A011782(n).

d:A041010|id:A01333|id:A000034
A041010(n)= A001333(n)*A000034(n).

id:A057087|id:A000129|id:A000079
A057087(n)= A000129(n+1)*A000079(n).

id:A074323|id:A010684|id:A016116
A074323(n+1) = A010684(n)*A016116(n).

id:A081294|id:A011782|id:A000079
A081294(n)= A011782(n)*A000079(n).

id:A083333|id:A016116|id:A001045
A083333(n) = A016116(n)*A001045(n+1).

id:A083332|id:A016116|id:A014551
A083332(n) = A016116(n)*A014551(n+1).

A084159(n) = A078057(n)*A001333(n). (probably trivial)

id:A084221|id:A074323|id:A016116
A084221(n) = A074323(n+1)*A016116(n).


id:A089499|id:A000129|id:A000034
A089499(n+1)= A000129(n+1)*A000034(n).

id:A094015|id:A016116|id:A000079
A094015(n) = A016116(n+1)*A000079(n). (probably easy)

id:A108475|id:A000129|id:A001333
A108475(n) = A000129(n+1)*A001333(n).

id:A108476|id:A002605|id:A026150
A108476(n) = A002605(n)*A026150(n).

Richard Mathar