[seqfan] Sequence to A141530
vincenzo.librandi at tin.it
vincenzo.librandi at tin.it
Thu Feb 12 12:14:04 CET 2009
I think that
a(n)=4*n^3+6*n^2-1
is equal to A141530
0 -1
1 9
2 55
3 161
4 351
5
649
6 1079
7 1665
8 2431
9 3401
10 4599
11 6049
12 7775
13
9801
14 12151
15 14849
16 17919
17 21385
18 25271
19 29601
20 34399
21
39689
22 45495
23 51841
24 58751
25 66249
26 74359
27 83105
28 92511
29
102601
30 113399
Regards,
Vincenzo Librandi
%I A141530
%S A141530 1,1,9,55,161,351,649,1079,1665
%V A141530 1,
-1,9,55,161,351,649,1079,1665
%N A141530 Third from a recurrences
family concerning numerators of a(i,j) square
defined
by j!*a(i,j)=Integral (from i to i+1) u*(u-1)*(-2)* .. *(u-j+1)
du. For recurrences,family begins at j=1 (not 0,hence
third of the
family instead of fourth). j=1: a(n)=a(n-1)
+2, A005408; j=2: a(n)=2a(n-1)-a(n-2)+12,
A140811; j=3:
a(n)=3a(n-1)-3a(n-2)+a(n-3)+24, this sequence; j=4:
4a
(n-1)-6a(n-2)+4a(n-3)-a(n-4)+720; j=5: 5a(n-1)-10a(n-2)+10a(n-3)-5a(n-4)
+a(n-5)+1440;
then Pascal A007318 without first 1's,
signed, followed with A0911317(j).
A091137(j) is ALSO a
(i,j) denominators, not A002790 as written in
A140825
modified Aug 6.
%C A141530 Initial terms of every sequence are given by
triangle online: 1; -1,
5; 1, -1, 9;
%Y A141530 Cf.
A141047, A141417.
%Y A141530 Sequence in context: A058852 A145875
A068970 this_sequence A016269 A005770
A030053
%Y
A141530 Adjacent sequences: A141527 A141528 A141529 this_sequence
A141531 A141532
A141533
%K A141530 sign,uned
%O A141530
0,3
%A A141530 Paul Curtz (bpcrtz(AT)free.fr), Aug 12 2008
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