[seqfan] Re: The last digit "d" of a(n) is present in a(n+1+d) --END

[Maximilian Hasler]

The links in http://www.research.att.com/~njas/sequences/A027678
might be useful for this problem.

Maximilian

On Tue, Feb 3, 2009 at 2:29 AM, Edwin Clark <eclark at math.usf.edu> wrote:
>> a(1) = 0
>> a(n+1) = smallest unseen square number sharing no digit with a(n).
> Candy sequence, yes. But interesting. I can find up to a(1202) = 1075369
> To go farther I need a square not in the list:
>    4, 484, 28224, 228484, 8282884
> whose digits are a subset of {4,2,8}. If my calculations are correct there
> are none with less than 15 digits. But surely there are more such squares.
>
>
>
>
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