[seqfan] Re: A154714

[Benoît Jubin]

Dear Neil,

I made a misprint, and in the line

%F A154714 f(2,x)=2.x; f(3,x)=2^x.x; f(4,x)=product(b(k),k=0..x) where
b(0)=0, b(m+1)=2^product(b(l), l=0..m). - Benoit Jubin, Jan 15 2009

b(0)=0 should be replaced by b(0)=x

Thank you,
Benoit


On Thu, Jan 15, 2009 at 4:25 AM, Benoît Jubin <benoit.jubin at gmail.com> wrote:
> On Thu, Jan 15, 2009 at 10:31 AM, Vladimir Reshetnikov
> <v.reshetnikov at gmail.com> wrote:
>> Hi,
>>
>> Can anybody calculate an upper bound for A154714(5)?
>> I believe that finding the exact value is unrealistic.
>
> I don't know if this helps but one has the formulas:
> a(n+1)=f(n,a(n))
> f(2,x)=2.x
> f(3,x)=2^x.x
> f(4,x)=product(b(k),k=0..x) where b(0)=0, b(m+1)=2^product(b(l),l=0..m)
>
> Regards,
> Benoit
>
>
>
>
>>
>> Thanks
>> Vladimir
>>
>>
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>