[seqfan] Re: Fun little identity (to me anyway)

avik roy avik_3.1416 at yahoo.co.in
Thu Jan 22 17:15:56 CET 2009

This identity can be more generalized:

[(n+p)^2 + k][n^2 + k] = [n(n+p) + k]^2 + kp^2;

This identity can contribute to expressing the product of sums of two squares as a sum of two squares [if k is a square].

As an illustration, check:

(3^2 + 2^2)*(10^2 + 2^2)=34^2 + 14^2

      Add more friends to your messenger and enjoy! Go to http://messenger.yahoo.com/invite/

More information about the SeqFan mailing list