[seqfan] Re: a(n)th term is twice a(n)
Eric Angelini
Eric.Angelini at kntv.be
Wed Jul 29 10:41:40 CEST 2009
[Jack Brennen]:
> It appears that the sequence repeats the pattern (...)
... yes, I've suspected smthg like this after working on
seq like:
Each term of S "says":
--> The a(n)th term of S is a(n)+k
To build S, always take the smallest available integer not
leading to a contradiction (and no repeats)
For k=1 or 2, or 3, or 4, ... patterns appear almost im-
mediately -- thanks Jack!
Best,
É.
-----Message d'origine-----
De : seqfan-bounces at list.seqfan.eu
[mailto:seqfan-bounces at list.seqfan.eu]
De la part de Jack Brennen
Envoyé : mardi 28 juillet 2009 20:23
À : Sequence Fanatics Discussion list
Objet : [seqfan] Re: a(n)th term is twice a(n)
I assume that you're not allowing repeats in the sequence...
It appears that the sequence repeats the pattern:
a(6x) = 6x+1
a(6x+1) = 12x+2
a(6x+2) = 12x+4
a(6x+3) = 6x+5
a(6x+4) = 12x+8
a(6x+5) = 12x+10
with only a sparse set of exceptions...
All but three of the exceptions fit this pattern:
a(6*2^n) = 12*2^n
a(6*2^n+1) = 6*2^n+2
a(9*2^n) = 18*2^n
a(9*2^n+1) = 9*2^n+2
And three small exceptions seem to complete the sequence:
a(3) = 1
a(5) = 6
a(7) = 9
Eric Angelini wrote:
> Hello SeqFans,
> could someone please check and compute a few more terms of S?
> Each term of S "says":
>
> --> The a(n)th term of S is 2*a(n)
>
> To build S, always take the smallest available integer not
> leading to a contradiction:
>
> n = 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 ...
> S = 2 4 1 8 6 12 9 16 18 11 22 24 14 28 17 32 34 36 20 40 23 44 46 48 26 52 29 56 58 31 62 64 ...
>
> Best,
> É.
>
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>
>
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