[seqfan] Re: Impressive A160972
peter.luschny
peter.luschny at googlemail.com
Tue Jul 28 15:40:39 CEST 2009
... abs(B(2n)/2n) ?
Well, this would be even more impressive ;-))
I mean numerator(abs(B(2n)/2n) ),
B(n) Bernoulli number of course.
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