Leroy Quet: > Example: 12 in binary is 1100. And 12 = 4^1 * 3^1 * 2^0 * 1^0. > The sequence of such n's begins: 1,2,6,12. > Does this sequence continue? If I understand this correctly, the next term is 576000 (10001100101000000000 in binary) = 20*16*15*12*10.