[seqfan] Re: A001055 Number of ways of factoring n with all factors>1
Joerg Arndt
arndt at jjj.de
Tue Mar 3 05:09:20 CET 2009
Shame on me for my earlier post...
I agree with the argument below,
please enter a comment into the sequence.
* David Wilson <davidwwilson at comcast.net> [Mar 03. 2009 10:57]:
> By factorization of n, we mean a multiset of integers >= 1 whose product is
> n.
>
> For example, 6 is the product of 2 such multisets, {2, 3} and {6}, so
> A001055(6) = 2.
>
> Similarly, 8 is the product of 3 such multisets, {2, 2, 2}, {2, 4} and {8},
> so A001055(6) = 3.
>
> 1 is the product of 1 such multiset, namely the empty multiset {}, whose
> product is by definition the multiplicative identity 1. Hence A001055(1) =
> 1.
>
> In other words, a(1) = 1 is consistent with the definition.
>
>
> [...]
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