[seqfan] A147296

[vincenzo.librandi at tin.it]

Comment: 

I believe the formula is

a(n)=n(9n+2)

(0, 11, 40, 87, 152, 
235, 336, 455, 592, 747, 920, 1111, 1320, 1547, 1792, 2055, 2336,  
2635, 2952, 3287, 3640,  4011, 4400, 4807, 5232, 5675, 6136, 6615, 
7112, 7627, 8160, 8711, 9280, 9867, 10472, 11095, 11736, 12395, 13072, 
13767, 14480, 15211, 15960, 16727, 17512, 18315,...,)

Regards,
Vincenzo Librandi