* c.zizka at email.cz <c.zizka at email.cz> [Nov 24. 2009 20:53]: > The correct formula : > > a(n)=n + digitsum ( (2^n-1)/(2*n-1) ) , digitsum in base 2. > > Ctibor > Using pari/gp: ? for(n=1,10,print((2^n-1)/(2*n-1)) ) 1 1 7/5 15/7 31/9 63/11 127/13 17 511/17 1023/19 What is the Hamming weight (your digitsum) of a rational?