[seqfan] Re: Close sequences again
chris.eveswell at virgin.net
Tue Oct 20 11:12:20 CEST 2009
n prime(n) floor(1^2/prime(n)) floor(2^2/prime(n))
1 2 0 -
2 3 0 1
I did ask for A166128 to be removed.
From: seqfan-bounces at list.seqfan.eu [mailto:seqfan-bounces at list.seqfan.eu]
On Behalf Of Michael Porter
Sent: 20 October 2009 09:12
To: Sequence Fanatics Discussion list
Subject: [seqfan] Re: Close sequences again
> (Sum of the quadratic non-residues of prime(n) - Sum of the quadratic
> residues of prime(n)) / prime(n). I discovered that this was equivalent
> (sum ( floor (j^2 / prime(n))), j = 1:prime(n) - 1) - floor ((prime(n) -
> 2)(prime(n) - 1) / 3) and that this could be extended to the naturals.
That seems like a non-trivial result, so I'm glad to see you have already
added it to OEIS (A165951). But for a(1) and a(2), prime(n)=2 and 3, the
expression evaluates to -1/2 and 1/3, right?
A166468 is the one we were discussing earlier, and if I read it correctly,
A166128 is just prime(n)-1 with a(1) set to 0, so a similar argument
applies. I can't seem to get to A166129 and A166130.
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