[seqfan] simple zero-divisors with Cayley-Dickson algebras
Joerg Arndt
arndt at jjj.de
Thu Sep 17 01:41:49 CEST 2009
Write A for the element (as a vector) where all
components are zero but component A is +1.
The most simple zero-divisors we have are
those of the form (A + B).
If (A+B) is a ZD, then all 4 of ( +-A +-B ) are ZDs.
Simple ZD are indeed both left and right ZD
(so always proper ZD).
Counting the ZD of the form (A+B) gives
n: 0, 1, 2, 3, 4, 5, 6, 7, 8,
ZD: 0, 0, 0, 0, 42, 294, 1518, 6942, 29886,
(note the number of all simple ZD is 4 times this one,
e.g. there are 168 simple ZD for the sedenions).
I conjecture the sequence is the same as the following:
? v=vector(14); v[4]=42;
? for(k=5,#v, v[k]=2*v[k-1]+(2^(k-1)-1)*(2^(k-1)-2) ); v
[0, 0, 0, 42, 294, 1518, 6942, 29886, 124542, 509694, 2064894, 8317950, 33400830, 133885950]
(this is via observing a very striking structure).
OEIS worthy?
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