[seqfan] Re: Mod[Fibonacci[n],n^2]<=Mod[Fibonacci[n],n]
Jay Anderson
horndude77 at gmail.com
Fri Apr 30 06:53:01 CEST 2010
On Thu, Apr 29, 2010 at 8:08 PM, zak seidov <zakseidov at yahoo.com> wrote:
> 1.
> Numbers n such that
> Mod[Fibonacci[n],n^2]<=Mod[Fibonacci[n],n]
> {1,2,3,4,12,45,177,1932,2189,4712,
> 5771,5778,43220}
> More terms?
[
1,
2,
3,
4,
12,
45,
177,
1932,
2189,
4712,
5771,
5778,
43220,
288176,
290422,
565181,
760763,
1244184,
1473817,
2842588,
2964627,
3100830,
]
Checked up through 5_000_000. I believe that
Mod[Fibonacci[n],n^2]==Mod[Fibonacci[n],n] holds for all these so far.
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