[seqfan] Inverse permutation is also the absolute value of the first diffs

[Andrew Weimholt]

This one was fun to work out by hand!

Construct a permutation of the positive integers (A) such that the
inverse permutation (B)
is also the absolute values of the first differences.

By hand, I get...

A = 1, 2, 4, 10, 13, 3, 19, 38, 16, 5, 9, 73, 48, 43, 23, 6, 15, 44,
7, 14, 41, 8,

B = 1, 2, 6, 3, 10, 16, 19, 22, 11, 4, 64, 25, 5, 20, 17, 9, 29, 37, 7, 27, 33,

This appears to be the earliest sequence that works up to this point.
I'm not absolutely sure that this beginning won't eventually lead to a
contradiction,
as I encountered some snares in my earlier attempts.

Andrew