[seqfan] Re: COMMENT FROM submitA Zak Seidov A179955

[Douglas McNeil]

>> %C A179955 Contribution from Zak Seidov
>> (zakseidov(AT)yahoo.com), Aug 06 2010: (Start)
>> %C A179955 There are exactly 509 terms. Numbers of n-digit
>> terms, for n=2..10 are
>> %C A179955 9,36,84,126,126,84,36,7,1. (End)

Aren't you're missing two 9-digit numbers, Zak?  I get:

[211111111, 121111111, 112111111, 111211111, 111121111, 111112111,
111111211, 111111121, 111111112]

for a total of 511 terms.  We agree on all other n-digit number counts.


Doug

-- 
Department of Earth Sciences
University of Hong Kong