[seqfan] Re: Permutations constructable from consecutive sums

Ron Hardin rhhardin at att.net
Sun Aug 15 23:24:32 CEST 2010



 

> 1,2,2,0,0,0,0,0,0,0,0,0,0,0,0,0,12,48,176,444,420,2124,8056
> Number  of permutations of 0..(n-1) representable as 1,4,6,4,1-weighted 
> consecutive  sums of 5 adjacent elements of a sequence of n+4 non-negative 
> integers

 The next wieghting in the series, 1,5,10,10,5,1 , yields a(n)=1,2,2,0,0,0... 
with 0's through at least n=32





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