[seqfan] Re: A158911

[Claudio Meller]

Ok, thanks Charles!
Claudio

2010/8/24 Charles Greathouse <charles.greathouse at case.edu>

> The sequence as written looks wrong.  I get
>
> 1, 3, 4, 7, 9, 15, 19, 24, 31, 39, 49, 63, 79, 99, 124, 127, 159, 199,
> 249, 255, 319, 399, 499, 511, 624, 639, 799, 999, 1023, 1249, 1279,
> 1599, 1999, 2047, 2499, 2559, 3124, 3199, 3999, 4095, 4999, 5119,
> 6249, 6399, 7999, 8191, 9999, 10239, 12499, 12799, 15624, 15999,
> 16383, 19999, 20479, 24999, 25599, 31249, 31999, 32767, 39999, 40959,
> 49999, 51199, 62499, 63999, 65535, 78124, 79999, 81919, 99999, 102399,
> 124999, 127999, 131071, 156249, 159999, 163839, 199999, 204799,
> 249999, 255999, 262143, 312499, 319999, 327679, 390624, 399999,
> 409599, 499999, 511999, 524287, 624999, 639999, 655359, 781249,
> 799999, 819199, 999999, 1023999, 1048575, 1249999, 1279999, 1310719,
> 1562499, 1599999, 1638399, 1953124, 1999999, 2047999, 2097151,
> 2499999, 2559999, 2621439, 3124999, 3199999, 3276799, 3906249,
> 3999999, 4095999, 4194303, 4999999, 5119999, 5242879, 6249999,
> 6399999, 6553599, 7812499, 7999999, 8191999, 8388607, 9765624,
> 9999999, ...
>
> with the naive
>
> is(n)=Mod(10,n+1)^n==0
>
> Charles Greathouse
> Analyst/Programmer
> Case Western Reserve University
>
> On Tue, Aug 24, 2010 at 4:05 PM, Claudio Meller <claudiomeller at gmail.com>
> wrote:
> > Hi,
> >
> > In http://www.research.att.com/~njas/sequences/A158911<http://www.research.att.com/%7Enjas/sequences/A158911>
> > (Numbers n such that 10^n divided thru the number of digits of 10^n is an
> > integer.)
> > are 124, 249, 299, 624, 999,1249, 1549, 2499,3999, 4999 and 7999 terms of
> > A158911?
> > --
> > Best
> > Claudio Meller
> >
> > _______________________________________________
> >
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> >
>
>
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-- 
Claudio
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