[seqfan] Re: d(n) = d(n-1)*d(n-2) & d(n) = d(n+1)*d(n+2)
Leroy Quet
q1qq2qqq3qqqq at yahoo.com
Fri Feb 12 21:07:02 CET 2010
I accidently labled sequence number 2 as sequence number "3". I will take this as a sign that I should also ask about the sequence (make this # 2):
2) Those integers n, n>=2, such that d(n) = d(n-1)*d(n+1).
Thanks,
Leroy Quet
[ ( [ ([( [ ( ([[o0Oo0Ooo0Oo(0)oO0ooO0oO0o]]) ) ] )]) ] ) ]
--- On Fri, 2/12/10, Leroy Quet <q1qq2qqq3qqqq at yahoo.com> wrote:
> From: Leroy Quet <q1qq2qqq3qqqq at yahoo.com>
> Subject: [seqfan] d(n) = d(n-1)*d(n-2) & d(n) = d(n+1)*d(n+2)
> To: seqfan at seqfan.eu
> Date: Friday, February 12, 2010, 7:48 PM
> Could someone calculate a few terms
> of these sequences, please? Are they in the EIS yet?
>
> 1) Those integers n, n>=3, such that d(n) =
> d(n-1)*d(n-2), where d(n) is the number of divisors of n.
>
> 3,24,..
>
> 3) Those positive integers n such that d(n) =
> d(n+1)*d(n+2).
>
> 96,...
>
> Thanks,
> Leroy Quet
>
> [ ( [ ([( [ ( ([[o0Oo0Ooo0Oo(0)oO0ooO0oO0o]]) ) ] )]) ] )
> ]
>
>
>
>
>
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