[seqfan] Digitsum of a(n) is visible in a(n+1)

[Eric Angelini]

Hello SeqFans,
here is another re-ordering of the Naturals:

The digitsum of a(n) is visible in the smallest
a(n+1) not yet present in S:

S=1,10,11,2,12,3,13,4,14,5,15,6,16,7,17,8,18,
  9,19,100,21,23,25,27,29,111,30,31,24,26,28,
  101,20,22,34,37,102,32,35,38,112,40,41,45,
  49,113,50,51,46,103,...

... this is computed by hand -- and fun to do!

---

The 'equivalent' seq. is much harder to write:

"Digitsum of a(n) is visible in a(n-1)", or (bet-
ter), "a(n) shows the digitsum of the smallest
a(n+1) not yet present in T":

T=1,10,19,9,18,8,17,7,16,6,15,5,14,4,13,3,12,2,
  11,29,20,101,28,26,24,22,110,37,21,...

More headaches than fun with this one!
Best,
É.