[seqfan] Re: definition of A002848
rhhardin at att.net
rhhardin at att.net
Tue Feb 9 22:37:33 CET 2010
The series appears to start
1 0 0 8 21 0 0 3040 20505
--
rhhardin at mindspring.com
rhhardin at att.net (either)
-------------- Original message ----------------------
From: Richard Guy <rkg at cpsc.ucalgary.ca>
>
> For m = 1, the unique solution is 1 + 2 = 3.
>
> For m = 4, there are 8 solutions:
>
> 1 5 6 1 5 6 2 5 7 1 6 7
> 2 8 10 3 7 10 3 6 9 4 5 9
> 4 7 11 2 9 11 1 10 11 3 8 11
> 3 9 12 4 8 12 4 8 12 2 10 12
>
> 2 4 6 2 6 8 3 4 7 3 5 8
> 1 9 10 4 5 9 1 8 9 2 7 9
> 3 8 11 3 7 10 5 6 11 4 6 10
> 5 7 12 1 11 12 2 10 12 1 11 12
>
> I don't think that we found all solutions
> for any larger values of m. Computers
> and computation have advanced quite a bit
> in the last 36 years, and some of you can
> probably push this quite a way. Nowakowski
> gives (some) solutions for m = 4k and
> 4k+1 for all k.
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