[seqfan] Re: definition of A002848

rhhardin at att.net rhhardin at att.net
Tue Feb 9 22:37:33 CET 2010


The series appears to start

1 0 0 8 21 0 0 3040 20505


--
rhhardin at mindspring.com
rhhardin at att.net (either)
  
-------------- Original message ----------------------
From: Richard Guy <rkg at cpsc.ucalgary.ca>

> 
> For  m = 1, the unique solution is  1 + 2 = 3.
> 
> For  m = 4, there are 8 solutions:
> 
> 1 5  6     1 5  6     2  5  7     1  6  7
> 2 8 10     3 7 10     3  6  9     4  5  9
> 4 7 11     2 9 11     1 10 11     3  8 11
> 3 9 12     4 8 12     4  8 12     2 10 12
> 
> 2 4  6     2  6  8    3  4  7     3  5  8 
> 1 9 10     4  5  9    1  8  9     2  7  9
> 3 8 11     3  7 10    5  6 11     4  6 10
> 5 7 12     1 11 12    2 10 12     1 11 12
> 
> I don't think that we found all solutions
> for any larger values of  m.  Computers
> and computation have advanced quite a bit
> in the last 36 years, and some of you can
> probably push this quite a way.  Nowakowski
> gives (some) solutions for  m = 4k  and
> 4k+1  for all  k.





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