[seqfan] Re: d(n) = d(n-1)*d(n-2) & d(n) = d(n+1)*d(n+2)

[Leroy Quet]

I accidently labled sequence number 2 as sequence number "3". I will take this as a sign that I should also ask about the sequence (make this # 2):

2) Those integers n, n>=2, such that d(n) = d(n-1)*d(n+1).

Thanks,
Leroy Quet


[ ( [ ([( [ ( ([[o0Oo0Ooo0Oo(0)oO0ooO0oO0o]]) ) ] )]) ] ) ]


--- On Fri, 2/12/10, Leroy Quet <q1qq2qqq3qqqq at yahoo.com> wrote:

> From: Leroy Quet <q1qq2qqq3qqqq at yahoo.com>
> Subject: [seqfan]  d(n) = d(n-1)*d(n-2) & d(n) = d(n+1)*d(n+2)
> To: seqfan at seqfan.eu
> Date: Friday, February 12, 2010, 7:48 PM
> Could someone calculate a few terms
> of these sequences, please? Are they in the EIS yet?
> 
> 1) Those integers n, n>=3, such that d(n) =
> d(n-1)*d(n-2), where d(n) is the number of divisors of n.
> 
> 3,24,..
> 
> 3) Those positive integers n such that d(n) =
> d(n+1)*d(n+2).
> 
> 96,...
> 
> Thanks,
> Leroy Quet
> 
> [ ( [ ([( [ ( ([[o0Oo0Ooo0Oo(0)oO0ooO0oO0o]]) ) ] )]) ] )
> ]
> 
> 
>       
> 
> 
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