[seqfan] p^2+6p+14

vincenzo.librandi at tin.it vincenzo.librandi at tin.it
Tue Jan 26 17:50:07 CET 2010


 Hi All,

because 

p^2+6p+14 (with p prime odd)

is prime for p=3

and for all prime is divisible for 3 ?

Regards,

Vincenzo Librandi 


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