[seqfan] p^2+6p+14
vincenzo.librandi at tin.it
vincenzo.librandi at tin.it
Tue Jan 26 17:50:07 CET 2010
Hi All,
because
p^2+6p+14 (with p prime odd)
is prime for p=3
and for all prime is divisible for 3 ?
Regards,
Vincenzo Librandi
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