[seqfan] Re: a puzzle sequebce
Robert Munafo
mrob27 at gmail.com
Mon Jul 26 05:34:15 CEST 2010
By the way, Terry's "one sequence in your Encyclopedia that begins 6, 42,
156" is A082986, and it does indeed agree with my sequence in all of its
terms (there are only two more terms: 420 and 930).
See http://www.research.att.com/~njas/sequences/A082986 or
http://oeis.org/wiki/A082986
On Sun, Jul 25, 2010 at 23:20, Robert Munafo <mrob27 at gmail.com> wrote:
> 0, 0, 6, 42, 156, 420, 930, 1806, 3192, 5256, 8190, 12210, 17556, 24492,
> 33306, 44310, 57840, 74256, 93942, 117306, 144780, 176820, 213906, 256542,
> 305256, ...
> MCS496267 : A[0] = 0; A[K+1] = A[K] + 4 K^3 + 2 K
>
> This is the "simplest" recurrence relation according to a weighted sum of
> terms in the recurrence formula. For background on the MCS system and
> algorithms see http://mrob.com/pub/math/MCS.html
>
> - Robert Munafo
>
> On Sun, Jul 25, 2010 at 20:57, N. J. A. Sloane <njas at research.att.com>wrote:
>
>>
>> - i dont know answer
>>
>> this was from Terry Stickel
>>
>> i'm at a hotelw
>> with pitiful wifi service by the way
>>
>> >From Terrystickels at aol.com Sun Jul 25 11:53:58 2010
>>
>> Neil:
>>
>> Hope this finds you well. A reader of mine sent me the following sequence
>> and swears there are enough terms in it to find the next number/s:
>>
>> 0,0, 6,42,156 . . .
>>
>> He goes on to say that the first zero is the " zeroth " term, the second
>> zero, of course, is the first term. I'm usually pretty good at cracking
>> these
>> and unless he has made a mistake in presentation, I don't have a clue as
>> to what this sequence is. I did find one sequence in your Encyclopedia
>> that
>> begins 6,42, 156 . . but I'm not sure if that is applicable here. Any
>> guesses?
>>
>> any ideas? - neil
>>
>
--
Robert Munafo -- mrob.com
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