[seqfan] Re: A169902: all ones(?)

[zak seidov]

May be it'd be more clearer: 

%N A169900 Earliest sequence such that a(i)*a(k) divides
 a((a(i)+a(k)) for all i>=1, k>=1

but still this does not preclude from "all ones" case
a(i)=1 for all i>=1

Zak

--- On Fri, 7/9/10, Andrew Weimholt <andrew.weimholt at gmail.com> wrote:

> From: Andrew Weimholt <andrew.weimholt at gmail.com>
> Subject: [seqfan] Re: A169902: all ones(?)
> To: "Sequence Fanatics Discussion list" <seqfan at list.seqfan.eu>
> Cc: "seqfaneu" <seqfan at seqfan.eu>
> Date: Friday, July 9, 2010, 6:00 PM
> On 7/9/10, zak seidov <zakseidov at yahoo.com>
> wrote:
> > According to
> >
> >  %N A169900 Earliest sequence such that xy |
> a(x+y) for all x>=1, y>=1,
> >
> >  the sequence should contain all ones:
> 1,1,1,1,1,1,1,1.
> >
> >  Zak
> 
> Not true!
> 
> Suppose x=3 and y=2
> then 2*3 | a(2+3)   which I read as 2*3
> divides a(2+3)
> which means
> a(5) must be divisible by 6.
> 
> Does " a|b " have another meaning besides "a divides b" ?
> 
> Andrew
>