[seqfan] Re: R: Re: A074506

[zak seidov]

Non cambia nulla, quindi anche se  (it)
= Nothing changes, so even if      (en)

--- On Sun, 7/18/10, vincenzo.librandi at tin.it <vincenzo.librandi at tin.it> wrote:

> From: vincenzo.librandi at tin.it <vincenzo.librandi at tin.it>
> Subject: [seqfan]  R: Re:  A074506
> To: mathar at strw.leidenuniv.nl
> Cc: seqfan at seqfan.eu
> Date: Sunday, July 18, 2010, 2:17 PM
> Thanks.
> Non cambia nulla, quindi anche se 
> a(n)=7*a(n-1)-12*a(n-2)+6 with a(0)=3, a(1)=8
> a(2)=7*8-12*3+6=26a(3)=7*26-12*8+6=92a(4)=7*92-12*26+6=338etc.
> 
> 1^n + 3^n +
> 4^n:a^n+b^n+1^n=(a+b)*a(n-1)-(a*b)*a(n-2)+(a-1)*(b-1)
> Best RegardsVincenzo
> 
> 
> 
> 
> ----Messaggio originale----
> Da: mathar at strw.leidenuniv.nl
> Data: 18-lug-2010 7.08 PM
> A: <vincenzo.librandi at tin.it>
> Ogg: Re:  A074506
> 
> 
> vl> Return-Path: <seqfan-bounces at list.seqfan.eu>
> vl> X-Original-To: mathar at strw.leidenuniv.nl
> vl> Delivered-To: mathar at strw.leidenuniv.nl
> vl> Date: Sun, 18 Jul 2010 08:00:13 +0200 (CEST)
> vl> From: "vincenzo.librandi at tin.it"
> <vincenzo.librandi at tin.it>
> vl> To: seqfan at seqfan.eu
> vl> 
> vl> For the controll:
> vl>  %F A074506 a(n)=7*a(n-1)-12*a(n-2)+6 with
> a(1)=3, a(2)=8 [From Vincenzo
> vl> Librandi (vincenzo.librandi(AT)tin.it), Jul 16
> 2010]
> 
> What I mean is:
> This is incorrect because a(0)=3, a(1)=8.
> 
> The formula a(n)=7*a(n-1)-12*a(n-2)+6 is correct (and the
> current
> formula with the 7 should be changed).