[seqfan] Re: Number of n-digit numbers the binary expansion of which contains k runs of 1's

[Charles Greathouse]

These new sequences are exact duplicates of existing sequences.  If
someone searches for them, they'll find the existing sequences first
even if we keep these sequences in.  The usual way to handle this is
to delete the duplicate and move its description and/or comments into
the new sequence as comments.

Along the same lines, I recently found that A164003 is a duplicate of
A005563 (though I can't show that this happens for all rows of A163280
-- for example, A028552 and A164004 differ on one point; higher
sequences will diverge further).  Now that's a trickier case, because
A164003 is slightly more established.  Should it be changed to a
,dead, sequence?  Deleted outright?  Kept with forwarding comments?  I
tend to favor the first... any opinions?

Charles Greathouse
Analyst/Programmer
Case Western Reserve University

On Fri, Jul 30, 2010 at 4:26 PM, Vladimir Shevelev <shevelev at bgu.ac.il> wrote:
> Sorry, but you do not give a proof of your statement (at least, I do not see the clearness of it). On the other hand, using generating functions, one can easily prove that, indeed, the number of n-digit binary numbers  containing k runs of 1's equals to C(n,2*k-1), while the number of n-digit binary numbers  containing k runs of 0's equals to C(n,2*k) (in the latter case  we suppose that (n,k) differs from (1,1)). But it is not a combinatirial proof. But, in my opinion, the  identities
> Sum{k-1,n-k}C(i,k-1)*C(n-i-1,k-1)=C(n,2*k-1),  Sum{i=k,n-k}C(i-1,k-1)*C(n-i,k)= C(n,2*k)
> do not give a cause to delete these sequences. Indeed, if somebody is interested to see a behavier of binary numbers with this point of view, then he over first terms easily find these sequences with the corresponding names, if they are in OEIS; further, in coments he will see all formulas. I think that these are sufficiently important characteristics of binary numbers which are not described in OEIS, and  not all, which are interested in binary numbers, are able to obtain such results immediately. Please, try  to find these descriptions without these sequences. You  obtain nothing ( in the best case you can see tables of the  binomial cofficients without the first zeros).
>  Of course, I do not insist on the publication of them. I think that it is a prerogative of Neil.
>
> Regards,
> Vladimir
>
>
>
> ----- Original Message -----
> From: Alois Heinz <heinz at hs-heilbronn.de>
> Date: Friday, July 30, 2010 19:40
> Subject: [seqfan] Re: Number of n-digit numbers the binary expansion of which contains k runs of 1's
> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
>
>> Both new sequences (A179867, A179868) should be deleted.
>>
>> C(n,5) and C(n,6) here gives the number of ways to choose the
>> positions
>> of the
>> leftmost 1 (leftmost 0) of the first, second, third run of 1's
>> (0's) of
>> the n digit
>> binary number.
>>
>> Alois
>>
>> Charles Greathouse schrieb:
>> > Sum{i=2,n-3})C(i,2)*C(n-i-1,2) is just binomial(n, 5) =
>> > n*(n-1)*(n-2)*(n-3)*(n-4)/120.  So assuming the formula
>> is correct,
>> > a(12) needs to be corrected and the keyword easy should be added.
>> >
>> > Charles Greathouse
>> > Analyst/Programmer
>> > Case Western Reserve University
>> >
>> >
>>
>>
>>
>> _______________________________________________
>>
>> Seqfan Mailing list - http://list.seqfan.eu/
>>
>
>  Shevelev Vladimir‎
>
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