[seqfan] Re: Fixing A173907
franktaw at netscape.net
franktaw at netscape.net
Tue Mar 23 04:14:45 CET 2010
Well, three more terms are 8^69+69^8 =
205688069665150755269371147819668813122841983204711281293004769,
9^76+76^9 =
3329896365316142756322307042065269797678257903507506764421250291562312417
, and 21^68+68^21 =
8145392978596353266562523042658226096498925896754725985800958011876889320
52096060144958129 (these are prime according to PARI).
If I haven't made any mistakes, these are the next 3..
Franklin T. Adams-Watters
-----Original Message-----
From: Charles Greathouse <charles.greathouse at case.edu>
What should be done with A173907?
Richard Mathar points out in a comment that the definition does not
match the terms given. The definition given actually corresponds to
A045344, so one solution would be to delete the sequence (and possibly
add a comment there). Another would be to change the definition to
disallow 1s which lead to the trivial solutions. Of course this would
leave only two terms, falling two short of the required four.
Charles Greathouse
Analyst/Programmer
Case Western Reserve University
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