[seqfan] n < 2^tau(n)

Leroy Quet q1qq2qqq3qqqq at yahoo.com
Sun May 30 14:38:38 CEST 2010


I just submitted this sequence.

%S A175495 1,2,3,4,6,8,10,12,14,15,16,18,20,24,28,30,32,36,40,42,44
%N A175495 Those positive integers n where n < 2^d(n), where d(n) = number of divisors of n. 
%C A175495 After the initial 1 in this sequence, the first integer in this sequence but not in A034884 is 44. 
%C A175495 This sequence is those n where A175494(n) = 1. 
%Y A175495 CF. A175494, A034884 
%K A175495 more,nonn
%O A175495 1,2

(By the way, A175494(n) = floor(n^(1/d(n))).)


Is this sequence (A175495) finite?

Thanks,
Leroy Quet

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