[seqfan] Re: a(n) is tau[a(n)+a(n+1)]
Maximilian Hasler
maximilian.hasler at gmail.com
Tue May 18 16:49:28 CEST 2010
I think the next term should be 17569637319163259504744306426508888
M.
On Tue, May 18, 2010 at 3:42 PM, Eric Angelini <Eric.Angelini at kntv.be> wrote:
>
> Hello SeqFans,
>
> If we decide that a(n) is tau[a(n)+a(n+1)], then
> a monotonically increasing sequence S of such terms
> could start like this:
>
> S = 2,3,6,12,48,2472,...
>
> Are more terms of S computable?
>
> If we drop the "monotonically increasing" constraint
> but add "all terms of T must be different -- always
> take the smallest available integer not leading to
> a contradiction", would T be different of S? [of course
> 0 and 1 are not allowed in T]
>
> Best,
> É.
>
>
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