[seqfan] Re: a(n) divides the sum of the first a(n) terms of S
franktaw at netscape.net
franktaw at netscape.net
Thu May 20 12:00:47 CEST 2010
However, if we take n divides the sum of the first n terms of S, with
the weaker restriction that no term can have occurred before, we get
the very beautiful http://www.research.att.com/~njas/sequences/A019444.
(I just submitted a formula for this:
Let s(n) = sum(k=1,n,a(k))/n = A019446(n). Then if s(n-1) does not
occur in a(1),...,a(n-1), a(n) = s(n) = s(n-1); otherwise, a(n) =
s(n-1) + n and s(n) = s(n-1) + 1.
and a corresponding PARI program.)
Franklin T. Adams-Watters
-----Original Message-----
From: franktaw at netscape.net
...
Of course n divides the sum of the first n terms of S is just the odd
numbers.
Franklin T. Adams-Watters
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