[seqfan] Re: A178253

Jeremy Gardiner jeremy.gardiner at btinternet.com
Mon May 24 14:22:27 CEST 2010


I get:

4,2,4,2,2,4,4,2,2,2,2,4,5,2,4,2,2,2,2,2,2,3,2,4,2,4,5,5,2,4,4,2,2,2,2,2,2,2,
2,2,4,2,2,2,3,2,2,4,3,2,2,5,4,5,3,2,5,2,3,4,3,2,4,2,2,2,2,2,2,4,2,2,2,2,2,2,
2,2,4,2,2,3,4,2,2,2,2,4,2,3,3,2,3,2,2,4,3,2,3,2,2,2,3,2,5,4,2,5,5,3,3,2,2,5,
2,2,2,4,3,4,2,5,3,3,2,4,4

Regards,
Jeremy Gardiner

On 24/5/10 11:44, "Vladimir Shevelev" <shevelev at bgu.ac.il> wrote:

> Dear seqfans,

I have just submitted the following sequence:

%I A178253
%S
> A178253 4,2,4,2,2,4,4,2,2,2,2,4
%N A178253 a(n) is the least number m such
> that (A001969(n))^m is in A000069 
%F A178253 If k=A001969(n)=2^m*A001969(s),
> where A001969(s) is odd, then a(n)=a(s). 
%Y A178253 A000069 A001969 
%K
> A178253 nonn
%O A178253 1,1
%A A178253 Vladimir Shevelev
> (shevelev(AT)bgu.ac.il), May 24 2010

Can anyone to extend it?

Best
> regards,
Vladimir

 Shevelev
> Vladimir?

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