# [seqfan] Re: Observations on some odd Fibonacci numbers

Thu Oct 7 09:23:31 CEST 2010

```Note that, condition ind G>sqrt(ind F) one can replace by weaker condition ind G is not equal to
sqrt(ind F) ( with the quite same proof). This allows to keep terms 987, 2178309, 102334155.
Now we conjecture that  sequence with the definition  "a(n) is the n-th odd Fibonacci number F with the property: F  has at least one  proper Fibonacci divisor G for which ind G not equals to sqrt(ind F) and  F/G has not a proper Fibonacci  divisor>3" contains all {F} which are represented in the form   F=F_1*Prod {i=1,...,m}L_i (F_1>=3, m>=1) and only them.
To prove this conjecture, we should prove that, for odd prime p, the ratio F_{p^2}/F_p
is not Lucas number or a product of Lucas numbers. Moreover, over

----- Original Message -----
From: Vladimir Shevelev <shevelev at bgu.ac.il>
Date: Wednesday, October 6, 2010 21:57
Subject: [seqfan] Re: Observations on some odd Fibonacci numbers
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>

> Thanks, Richard, for counter-examples.
>
> Note  that F_{98} has divisor G_0=F_{49}. Therefore,
> F_{98} is not a counter-example
> in a wider sense (see my previous seqfan-massage). On the other
> hand, it is interesting that the other
> first indices that are 7^2,11^2,13^2. Moreover ( since F_m|F_n
> iff m|n), the corresponding indices of G are 7,11,13. I think
> that  the sequence of counter-examples contains other
> values of prime^2;
> moreover, it seems that, for odd prime p, the ratio F_{p^2}/F_p
> does not contain any Lucas number.
>
> Let us prove that, in order to avoid the counter-examples, it is
> sufficient to introduce a weak restriction on  G:
> indG>sqrt(ind F), such that  the corrected definition is:
> "a(n) is the n-th odd Fibonacci number F with the property: F
> has at least one  proper Fibonacci divisor G for which ind
> G>sqrt(ind F) for which  F/G has not a proper Fibonacci
> divisor>3".
> Show that for a(n) there exists at least one of  such
> divisor G=G_0 for which the ratio F/G_0 is a Lucas number or
> product of some Lucas numbers.
> Indeed, let a(n)=F_m. Since F_m is odd, then, as it is well-
> known, m is not multiple of 3. Furthermore, if m is even, then
> F_m has required representation ( see message by Tony). The case
> m=p^2, where p is prime, is impossible by the condition. The
> case m=p is impossible as well, since
> F_p has not a proper Fibonacci divisor. Finally, if m=p*l or
> m=p^2*l, where l is odd and not multiple of 3, then, evidently,
> for every proper divisor d>1 of m, m/d is also a proprer divisor
> of m. Thus, F_d and F_{m/d} are  proper divisors of F_m,
> such that, for every G, a(n) contains also the proper divsor
> a(n)/G>3. It is impossible by the condition. This completes proof.
>
>   The first terms of the sequence are:
>
> 21,55,377,6765,17711,121393,317811,5702887,39088169, 701408733,
> 1836311903,...
> But now the sequence differs from sequence of {F} which are
> represented in the form
>  F=F_1*Prod {i=1,...,m}L_i (F_1>=3, m>=1) ( e.g., 987,
> 2178309, 102334155 are excluded).
>
>
> Best regards,
>
>
>
>
> ----- Original Message -----
> From: Richard Mathar <mathar at strw.leidenuniv.nl>
> Date: Tuesday, October 5, 2010 18:54
> Subject: [seqfan] Re: Observations on some odd Fibonacci numbers
> To: seqfan at seqfan.eu
>
> >
> > http://list.seqfan.eu/pipermail/seqfan/2010-October/006140.html
> >
> > vs>    I consider the following subsequence of
> > Fibonacci numbers:
> > vs>
> >
> 21,55,377,987,6765,17711,121393,2178309,5702887,39088169,1836311903,...vs> with the definition: a(n) is the n-th odd Fibonacci number F with the
> > vs> property: F has a proper Fibonacci divisor G>1, but F/G
> has
> > not.
> >
> > Note also that 6765 is not in my list because 6765 = 3*2255
> > where 2255 has a proper Fibonacci divisor (that is, 55). So my
> > interpretationof the definition is that no odd F with two
> proper
> > divisors in A000045
> > are in a(n). I am not sure whether to admit cases where F has
> > proper
> > Fibonacci divisors G of both types.
> >
> > vs> I noticed (without a proof) that F/G is a Lucas number or
> a
> > product of
> > vs> some Lucas numbers.
> >
> > The examples
> > n= 49, F=7778742049, G=13, F/G=598364773, Lprod=false
> > n= 98, F=135301852344706746049, G=13,
> F/G=10407834795746672773,
> > Lprod=falsen= 121, F=8670007398507948658051921, G=89,
> > F/G=97415813466381445596089, Lprod=false
> > n= 169, F=93202207781383214849429075266681969, G=233,
> > F/G=400009475456580321242184872389193, Lprod=false
> >
> > are the first counter-examples according to my calculation
> which
> > are in the
> > list of these a(n) where F/G is not a Lucas number or product
> of such.
> >
> > http://mersennus.net/fibonacci/f1000.txt
> > J Brillhart et al, "Tables of Fibonacci and Lucas
> > Factorizations" Math Comp 50 (1988) 252,
> > http://www.jstor.org/stable/2007928
> >
> > _______________________________________________
> >
> > Seqfan Mailing list - http://list.seqfan.eu/
> >
>