[seqfan] Re: trouble with A132337 and A132336
Donald Alan Morrison
donmorrison at gmail.com
Fri Oct 8 21:45:32 CEST 2010
Also, how is 1 dealt with? Is it considered a 6th power?
On Fri, Oct 8, 2010 at 12:34 PM, Donald Alan Morrison
<donmorrison at gmail.com> wrote:
> On Fri, Oct 8, 2010 at 12:10 PM, N. J. A. Sloane <njas at research.att.com> wrote:
>> Dear SeqFans, I received some emails from Daniel Mondot <dmondot at gmail.com>
>> who has been looking at A132337. He says:
>>
>> (Start)
>> If the intent of A132337 is really
>> "a(n) is the sum of all numbers from 0 to n not counting the n's that
>> are a 6th power" then the series should be:
>> 0, 2, 5, 9, 14, 20, 27, 35, 44, 54, 65, 77, 90, 104, 119, 135, 152, 170,
>>[...]
>
> Which of the following possibilities are included in the "6th power" definition:
> 1) A prime to the 6th power.
> 2) A prime to a power a multiple of 6.
> 3) A prime factorization with all exponents equal to 6.
> 4) A prime factorization with all exponents equal to a multiple of 6.
> 5) A prime factorization with all exponents equal to some multiple of
> 6 not necessarily equal to each other. For example: 177978515625 ==
> (3^6) * (5^12)
>
> If I know which power definition is being referenced, I can write a
> few lines of code to verify/rectify.
>
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