[seqfan] Re: Checking A174216

Max Alekseyev maxale at gmail.com
Fri Oct 29 23:11:26 CEST 2010


I confirm that a(11)=18927.

Here is my PARI/GP code for A174216, starting with the second term and
listing all terms below 10^5:

{ a=14; for(n=10, 10^5, if( gcd(a,n-1-(-1)^n)==1, a+=1, a=2*n-4); if(
2*a==3*(n-1), print1(n,", ") )) }

27, 63, 123, 279, 567, 1143, 2307, 4623, 9447, 18927, 38283, 77139,

Regards,
Max

On Fri, Oct 29, 2010 at 4:04 PM, Richard Mathar
<mathar at strw.leidenuniv.nl> wrote:
>
> In March, I changed A174216(11) to 18927, which was reverted
> by the author of the sequence to 19263. Can someone independently
> check the terms in A174216?
> This concerns primarily n=11, k=18927 with A174214(k)=232257 and
> 3*(k-1)=464514 (all values according to my calculation).
>
> http://oeis.org/classic/?q=id%3AA174214|id%3AA174216
>
>
>
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