[seqfan] Re: A175781: What if n is 6th power (as 64) - n^(1/2)?
Maximilian Hasler
maximilian.hasler at gmail.com
Sat Sep 4 15:12:03 CEST 2010
> I do not care which so long as it is specified.
But any additional specification will be somehow artificial
and won't make it very natural compared to e.g.
A052410 = smallest k for which n = k^m for some m.
Another way to resolve the ambiguity without being more artificial
would be to let
a(n) = n^(1/k) with the smallest k>1 such that n is a k-th power, k=1
if no such k>1 exists.
This would reproduce a(64)=8, but change a(32) to 2.
> Also this sequence should be Cf.'d to A007947.
and A052410 should be xref'd too, IMO.
BTW, the offset is incorrectly set to 1, but given data starts with a(0)=0.
M.
> --------------------------------------------------
> From: "zak seidov" <zakseidov at yahoo.com>
> Sent: Saturday, September 04, 2010 6:05 AM
> To: "seqfaneu" <seqfan at seqfan.eu>
> Subject: [seqfan] A175781: What if n is 6th power (as 64) - n^(1/2)?
>
>>
>> %S A175781 0,1,2,3,2,5,6,7,2,3,10,11,12,13,14,15,4,17,18,19,20,21,
>> 22,23,24,5,26,3,28,29,30,31,32,33,34,35,6,37,38,39,40,
>> 41,42,43,44,45,46,47,48,7,50,51,
>> 52,53,54,55,56,57,58,59,60,61,62,63,8,65,66,
>> 67,68,69,70,71,72,73,74,75
>> %N A175781 If n is square or cube replace with n^(1/2) or n^(1/3)
>>
>> What if n is 6th power (as 64) - n^(1/2)? (as 8?).
>>
>>
>>
>>
>>
>>
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