[seqfan] Re: g.f. for a(n)= a(n-1)*2^n+n, a(0)=1 ?
Robert G. Wilson v
rgwv at rgwv.com
Sun Sep 5 17:21:01 CEST 2010
Georgi,
I tried to find one using Mathematica "findgeneratingfunction" but it
returned nothing.
Bob.
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From: "Georgi Guninski" <guninski at guninski.com>
Sent: Sunday, September 05, 2010 9:31 AM
To: <seqfan at seqfan.eu>
Subject: [seqfan] g.f. for a(n)= a(n-1)*2^n+n, a(0)=1 ?
> i tried to submit:
> a(n)= a(n-1)*2^n+n, a(0)=1
>
> it satisfies both:
> a(n+1) = (2^(n + 1) + 1)*a(n) - 2^n*a(n - 1) + 1
>
> a(n+1) = ((a(n - 2) + 4*a(n - 1) + 4)*a(n) - 2*a(n - 1)^2 - 4*a(n)^2 +
> a(n - 2) - 4*a(n - 1))/(a(n - 2) - 2*a(n - 1))
>
> and is kind of related to:
> A010842 a(n) = n*a(n-1)+2^n
>
> superseeker fails to find g.f., does anyone know one ?
>
>
>
>
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