[seqfan] Re: (a+b) divides the concatenation [a,b]
Eric Angelini
Eric.Angelini at kntv.be
Tue Sep 21 18:20:42 CEST 2010
> Dropping the monotonically increasing
> constraint would give V -- which I haven't
> looked at yet.
... I hope I didn't make my usual mistake too
soon:
V = 1,2,4,5,10,8,14,7,26,13,20,16,17,34,32,12,6,3,30,15,18,9,
24,42,21,56,28,35,64,68,31,62,37,74,25,50,40,48,51,102,...
Rule:
« Smallest integer not yet present in V such
that [a(n)+a(n+1)] divides the concatenation
of [a(n),a(n+1)] »
Example here:
1+2 divides 12 -> 12/3=4
2+4 divides 24 -> 24/6=4
4+5 divides 45 -> 45/9=5
5+10 divides 510 -> 510/15=34
10+8 divides 108 -> 108/18=6
8+14 divides 814 -> 814/22=37
...
Best,
É.
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