[seqfan] Re: Two thingies with digits

israel at math.ubc.ca israel at math.ubc.ca
Tue Aug 16 06:40:48 CEST 2011


Also, anything ending in 01 or 98 or 99 is out.

Robert Israel                                israel at math.ubc.ca
Department of Mathematics        http://www.math.ubc.ca/~israel 
University of British Columbia            Vancouver, BC, Canada

On Aug 15 2011, israel at math.ubc.ca wrote:

>Also e.g. 123456789 can't be in S.  In fact 102345 can't either. 
>
>Robert Israel                                israel at math.ubc.ca
>Department of Mathematics        http://www.math.ubc.ca/~israel 
>University of British Columbia            Vancouver, BC, Canada
>
>
>On Aug 15 2011, Alois Heinz wrote:
>
>>
>>Dear Eric,
>>
>>S starts:
>>
>>1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 13, 14, 15, 17, 16, 18, 12, 21, 19, 25,
>>22, 23, 26, 24, 27, 28, 29, 31, 33, 32, 34, 35, 36, 38, 39, 41, 42,
>>43, 37, 44, 45, 46, 47, 48, 51, 149, 53, 49, 52, 54, 55, 56, 57, 59,
>>58, 63, 64, 65, 66, 67, 68, 62, 69, 72, 73, 75, 85, 77, 74, 76, 78,
>>82, 79, 83, 84, 86, 88, 89, 111, 91, 113, 87, 115, 93, 92, 94, 114,
>>108, 116, 106, 117, 105, 118, 104, 119, 81, 139, 61, 141, 95, 131, 71,
>>133, 109, 135, 107, 137, 143, 134, 136, 138, 154, 144, 145, 147, 146,
>>151, 96, 161, 97, 171, 129, 174, 126, 177, 127, 176, 124, 179, 103,
>>159, 148, 152, 155, 165, 142, 158, 164, 156, 166, 157, 167, 168, 162,
>>172, 128, 175, 125, 178, 122, 181, 169, 184, 121, 182, 185, 188, 112,
>>191, 186, 189, 211, 192, 194, 311, 153, 251, 193, 212, 187, 206, 205,
>>208, 203, 238, 207, 209, 202, 229, 215, 218, 216, 217, 183, 221, 219,
>>225, 222, 223, 226, 227, 173, 231, 213, 195, 252, 196, 261, 197, 271
>>
>>Note that S is NOT a permutation of N, missing numbers are:
>>10,20,30,40,50,60,70,80,90, ... this is because when you add 10, ...
>>the digit at the rightmost position of the previous number will be shared.
>>
>>Best, Alois
>>
>>Am 15.08.2011 10:49, schrieb Eric Angelini:
>>>   Hello SeqFans,
>>>   First, could someone please compute a hundred or so terms of S
>>>   where two consecutive terms of S share no digit with their sum?
>>>   This is http://oeis.org/A129562 dropping the "increasing" cons-
>>>
>>>   traint. I guess S starts:
>>>   S = 1,2,3,4,5,6,7,8,9,11,13,14,15,17,16,18,12,21...
>>>   Note that S is now a permutation of N. (Hope I didn't overlook S
>>>   in the OEIS.)
>>
>>
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