[seqfan] Re: Observation on A002865 Number of partitions of n that do not contain 1 as a part.

[William Keith]

On Thu, Feb 17, 2011 at 1:25 PM, David Scambler <dscambler at bmm.com> wrote:

> Apparently for any m>=n a(n) is also the number of partitions of m that sum
> to n if 1's are ignored.
>
> Is this obvious?
>

The partitions of m with exactly r 1s consist of all the possible partitions
of m-r with parts at least 2, followed by a string of r 1s.

William J. Keith