[seqfan] Re: a sequence to check
franktaw at netscape.net
franktaw at netscape.net
Tue May 10 21:49:17 CEST 2011
Also working basically by hand, but cross-checking A000219 and A098859,
I get a(6) = 32, not 31. I also get a(7) = 68, so the sequence starting
at n=0 is:
1,1,3,4,11,20,32,68
For n=6, by partition: [6]->1, [3^2]->2, [4,1^2]->3, [2^3]->3,
[3,1^3]->5, [2,1^4]->7, [1^6]->11.
Franklin T. Adams-Watters
-----Original Message-----
From: David Newman <davidsnewman at gmail.com>
I'd like someone to check (and extend) the following.
What is the number of plane partitions each of whose summands is used a
different number of times.
As an example for n=3 there are 4 such partitions
3
111
11
1
and
1
1
1.
The plane partitions
21 and
2
1
do not appear on the list because each of the summands "2" and "1" is
used
the same number of times.
The numbers that I've gotten, for n=1 until n=6, by hand calculations
are:
1,3,4,11,20, and 31
More information about the SeqFan
mailing list