[seqfan] Re: Digits concatenation

Paolo Lava paoloplava at gmail.com
Thu Nov 10 15:21:15 CET 2011


Claudio,

thank a lot for your calculation!

Paolo

2011/11/10 Claudio Meller <claudiomeller at gmail.com>

> HI Paolo, seqfans, I found this values:
> without 0:
>
> a(6)= 2346/51= 46, a(7)= 3426/571=6, a(8)= 3456/1728 = 2 a(9)= 13458/6729=2
>
> with 0:
>
> a(6)= 304/152=2, a(7)= 1046/523=2, a(8)= 10352/647=16, a(9)= 10476/5328=2
>
> Best,
>
> 2011/11/10 Paolo Lava <paoloplava at gmail.com>
>
> > Dear SeqFans,
> >
> >
> >
> > I am thinking to a sequence where at any step “n” we concatenate all the
> > digits of all the natural numbers from 1 to n in order to build up two
> > numbers x and y that minimize the ratio x/y, being x/y integer (leading
> > zeros not admitted).
> >
> >
> >
> > Starting with a(1)=1 we have a(2)=2 because 2/1=2, a(3)=4 because 12/3=4,
> > a(4)=33 because 132/4=33, a(5)=38 because 532/14=38, etc.
> >
> >
> >
> > If we start from a(0)=0 we have a(1)=0 (0/1), a(2)=5 (10/2), a(3)=34
> > (102/3), a(4)=3 (102/34), etc.
> >
> >
> >
> > Is there anybody who is willing to compute additional terms?
> >
> >
> >
> > Thanks
> >
> >
> >
> > Paolo
> >
> > _______________________________________________
> >
> > Seqfan Mailing list - http://list.seqfan.eu/
> >
>
>
>
> --
> Claudio Meller
> http://grageasdefarmacia.blogspot.com
> http://todoanagramas.blogspot.com/
> http://simplementenumeros.blogspot.com/
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>



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