[seqfan] Re: Chewing an old bone
David Wilson
davidwwilson at comcast.net
Mon Oct 24 15:48:03 CEST 2011
From looking at the old code, the scatter plot scale was as follows:
For small graphs, a(n)
For large nonnegative graphs, log(a(n)+1)
For large negative graphs, log(|a(n)|+1)
Except for graph title, this is equivalent to
For small graphs, a(n)
For large graphs, log(|a(n)|+1)
The criterion for deciding what is a large graph is complicated, based
on a sample of five elements. Personally, I would have chosen a log plot
based on some simpler criterion, say if |a(n)| or max(a)-min(a) exceeds
some constant N.
Currently, the qlog plot is supplementary to the log plot, if I
understand Russ
Cox correctly, this situation is provisional, and if the qlog plot works
out, it
will replace the log plot. By this I mean that a(n) scatterplot will
appear when
it now does, the qlog scatterplot will appear when the log plot now does.
I don't think it is much of a decision: look at, say, A000055, apart
from titles,
the log and qlog plots are visually identical for nonnegative
sequences. If you
then look at, say, A055615, you see the advantage of the qlog plot over the
log plot re showing negative values.
On 10/23/2011 11:28 PM, Benoît Jubin wrote:
> Is it normal that there is a scatter plot of qlog for every signed
> sequence, even when there is no scatter plot of log (because the
> sequence assumes only small values in the displayed interval; see
> https://oeis.org/A002321/graph)?
>
> Also, this is nitpicking, but there is some discrepancy in the titles
> of all the graphs: "Pin plot of Axxxxx" and "Scatterplot of Axxxxx(n)"
> (one or two words, and with or without argument).
>
> Thanks for the addition of the qlog graphs, and I agree with previous
> posts that it should stay "in addition to" log, and not "instead of".
>
> Benoit
>
> On Sun, Oct 23, 2011 at 5:00 PM, David Wilson<davidwwilson at comcast.net> wrote:
>> On 10/23/2011 5:23 PM, Russ Cox wrote:
>>> Sounds good. I have installed the graph:
>>>
>>> https://oeis.org/A103718/graph
>>>
>>> Russ
>>>
>> Thank you all for putting up with me regarding this.
>>
>>
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